The base pyramid below has a dimension of 16" x 16" a slant height of 17 inches in an altitude of 15 inches find the total surface area

800 in²

Step-by-step explanation:

Applying,

TSA (A) = Area of the base+ Lateral area of the

A = lw+1/2ps Equation 1

Where l = lenght of the base, w = width of the base, p = perimeter of the base, s = slight height of the base.

But,

p = 2(l+w) Equation 2

Substitute equation 2 into equation 1

A = lw+1/2[2(l+w)s)

A = lw+s(l+w) Equation 3

From the question,

Given: l = 16 in, w = 16 in, s = 17 in

Substitute these values into equation 3

A = (16×16)+17(16+16)

A = 256+544

A = 800 in²

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.