What is the flow rate of the air in the pipeline if the cross sectional area of a pneumatic pipeline is 0.01 m2 and the speed of the air in the pipeline is 20 m/s?

0.2 m³/s

Step-by-step explanation:

Applying,

Q = vA Equation 1

Where Q = Flow rate of  air in the pipeline, v = flow velocity of the air in the pipeline, A = cross sectional area of the pneumatic pipeline.

From the question,

Given: v = 20 m/s, A = 0.01 m²

Substitute these values into equation 1

Q = 20(0.01)

Q = 0.2 m³/s

Hence the flow rate of air in the pipeline is  0.2 m³/s

bru

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0