What is the perimeter of △ABC?
Round each step to the nearest tenth.

9514 1404 393

  15.8

Step-by-step explanation:

The distance formula is ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

so the distance from A to B is ...

  AB = √((-1-5)^2 +(1-(-1))^2) = √((-6)^2 +2^2) = √40 ≈ 6.3

Lengths BC and CA are similarly computed. (A spreadsheet does this nicely.)

The perimeter is the sum of the side lengths. It is ...

  P = AB +BC +CA

  P = 6.3 + 4.1 + 5.4

  P = 15.8

The perimeter of ∆ABC is 15.8 units.

throw the computer

step-by-step explanation:

answer: the correct option is d.

explanation:

it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.

from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then

    (1)

distance formula,

put these values in equation (1).

therefore scale factor is     and option d is correct.