I’m failing I really need help please!

3 and -4

Step-by-step explanation:

this is simple but difficult

let the number be x and second number be y

3x + 2y=1

x-y/2=5

from the 2nd equation

x-y/2=5

x=5+y/2

substitute value for x into equation 1

3x + 2y=1

3(5+y/2) + 2y= 1

15 +3y/2 +2y=1

15 + 7y/2=1

7y/2= 1 - 15

7y/2=-14

cross multiply

7y= -28

y= -28/7

y= -4

therefore second number is -4

substitute value for y into 1st equation

3x + 2y=1

3x + 2(-4) = 1

3x - 8= 1

3x= 1+8

3x= 9

x= 9/3

x= 3

therefore first number is 3

therefore two numbers are;

3 and -4

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.