2. A bag contains 5 red marbles, 3 blue marbles, 6 white marbles, and 2 green marbles. A. You choose one marble at random. Find the probability that you will choose a
white marble.
B. You choose one marble at random. Find the probability that you do not choose a red
marble.
I
C. You choose one marble at random, put the marble aside, then choose a second
marble at random. What is the probability that both marbles are blue?
D. You choose one marble at random, put the marble back in the bag, then choose a
second marble at random. What is the probability that you choose a red marble
and then a green marble?

Step-by-step explanation:

5 red

3 blue

6 white

2 green

total 16 marbles.

Note: P(E) = probability of event E happening

P(~E) = probability of event E NOT happening.

We usually leave probabilities in fractions whenever possible because they will not be subject to round-off errors.

A. choose one marble at random.

P(W) = 6 white / 16 total = 3/8

B. choose one marble at random.

P(~R) = (16-5)/16 = 11/16

C. choose one marble at random, then a second one without replacement,

there will be 3 blue out of 16 at the beginning, then if successful, there will be 2 blue out of 15.

P(BB) = (3/16)*(2/15) = 1 / 40

D. choose two with replacement

5 red out of 16 for first draw, still 5 red out of 16 for second draw.

P(RR) = (5/16)^2 = 25/256

step-by-step explanation:

in which figure is point g a centroid

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1