You are jumping on a trampoline. For one jump, your height y (in feet) above the trampoline after t seconds can be represented by y= -16t^2+24t. How many seconds are you in the air?

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Step-by-step explanation:

The person in this question is in the air whenever the height is greater than .

The graph of is a parabola opening downwards. Rearrange and find values of that would set this expression to .

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The first factor, , suggests that would set this expression to - quite expected, since the person is on the ground right before jumping.

The second factor, , suggests that (in other words, ) would also set this expression to . Hence, this person would be once again on the ground seconds after jumping.

Hence, this person is in the air between and for a total of .

$450

step-by-step explanation:

first, you have to multiply 150x2=300

next, you have to add 150+300= 450

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.