Diana averages 6 mph walking to school. Averaging 35 mph on
the way back home by car, she
takes 3 hour less time.
How far is the school
from her home?

Distance between school and home = 105 miles.

Step-by-step explanation:

Let distance = D miles

Time to take walking/jogging, t1 = D/6 hours

Time by car, t2 = D/35 hours

Average time, t

= (t1+t2)/2

= D(1/6+1/35)

= (D/210)(35+6)

=41D/210 hours

Given t = t1-3 hours

41D/210 - D/6 = 3

Solve for D

41D/210 - 35D/210 = 3

(41-35)D/210 = 3

6D/210 = 3

D = 3*210/6 = 105 miles.

(Appreciate very much Diana's efforts to walk/job 105 miles to school, and we understand how lucky we are in most of Europe and North America)

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq