Determine the perimeter of a regular octagon that has a distance from its center to any of its vertices of 10 inches. Round your answer to the nearest tenth of an inch.

61.2 in

Step-by-step explanation:

Draw a segment from O perpendicular to AB forming a right triangle.

Call the point of intersection J.

m∠HAB = (8 - 2)180/8 = 135

m∠BAO = 135/2 = 67.5

AJ/10 = cos 67.5

AJ = 10 cos 67.5

AB = 2(10 cos 67.5)

Perimeter = 8(AB) = 8(2)(10 cos 67.5) = 61.2 in.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

justin bieber ml.