The sides of a triangle are x cm, (x -1) cm and (x+2) cm. IF the perimeter is 31 cm, then the SHORTEST side is

9 cm

Step-by-step explanation:

Applying,

P = a+b+c Equation 1

Where P = Perimeter of the triangle, a, b,c are the three sides of the triangle respectively.

From the question,

Given: P = 31 cm, a = x cm, b = (x-1) cm, c = (x+2) cm

Substitute these values into equation 1, and solve for x

31 = x+(x-1)+(x+2)

31 = 3x+1

3x+1 = 31

3x = 31-1

3x = 30

divide both side by 3 to get x

3x/3 = 30/3

x = 10.

Therefore,  the sides of the triangle are

a = x = 10 cm,

b = (x-1) = (10-1) = 9 cm

c = (x+2) = (10+2) cm = 12 cm

Hence the shortest side is 9 cm

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8