Can anybody help with this question or at least help me solve one thanks

Step-by-step explanation:

1) the triangle on the right is half of an equilateral one, so the minor leg is 9

the left one has the two legs congruent

so we have

2x^2 = 81

x^2 = 81/2

x = 9/√2 = 9/2 √2 (at the numerator)

2) the top triangle has the congruents leg

hypotenuse^2 = 2(6√6)^2

hypotenuse^2 = 2(216)

hypotneuse^2 = 432

hypotenuse = √2^4 * 3^2 * 3

hypotenuse = 12√3

the triangle in the bottom is half of the an equilateral one, so

x = 12√3 * 2 = 24√3

3) the left triangle has congruent legs

7^2 = leg^2 + leg^2

49 = 2leg^2

leg^2 = 49/2

leg = 7/√2 = (7√2)/2

the right triangle is half of an equilateral one

x = 7√2/2 * √3 =  7/2 √6 (at the numerator)

4) the rifht triangle has two congruent legs

hy^2= 2(7√6)^2

hy^2 = 2(294)

hy^2 = 588

hy = √2^2 * 7^2* 3

hy = 14√3

the triangle on the left is half of an equilteral one: so

x = 14

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