A motorboat travels 441 kilometers in 9 hours going upstream and 388 kilometers in 4 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?

The rate of the boat in still water is 73 km per hour, and the speed of the current is 24 km per hour.

Step-by-step explanation:

Given that a motorboat travels 441 kilometers in 9 hours going upstream and 388 kilometers in 4 hours going downstream, to determine what is the rate of the boat in still water and what is the rate of the current, the following calculation must be performed:

Upstream = 441/9 = 49 km per hour

Downstream = 388/4 = 97 km per hour

(97 + 49) / 2 = X

146/2 = X

73 = X

97-73 = 24

49-74 = -24

Therefore, the rate of the boat in still water is 73 km per hour, and the speed of the current is 24 km per hour.

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5