A certain television is advertised as a 95-inch TV (the diagonal length). If the width of the TV is 77 inches, how tall is the TV? Round to the nearest tenth of an inch.

No ㅤ

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3x^3-x^2+6x-9

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet