How do I solve 2x^2-32=0 using the square root method?

x = -4,4

Step-by-step explanation:

2x^2 - 32 = 0

2x^2 = 32

x^2 = 16

x = either -4, 4

If there is only space for one answer put 4.

Hope this helped!

4 or -4

Step-by-step explanation:

2x^2-32+32=0+32

2x^2=32

1/2*2x^2=32*1/2

x^2=16

x=4 or -4