Solve mixture problems. George wishes to increase the percent of acid in 50m / of a 15% acid solution in water to 25% acid, how much pure acid must you add?

x = amount of pure acid to be added = 6.67ml

Step-by-step explanation:

George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?

let

x = amount of pure acid to be added

15% of 50 + x = 25% of 50 + x

(0.15 * 50) + x = 0.25(50 + x)

7.5 + x = 12.5 + 0.25x

Collect like terms

x - 0.25x = 12.5 - 7.5

0.75x = 5

x = 5/0.75

x = 6.6666666666666

Approximately,

x = 6.67

x = amount of pure acid to be added = 6.67ml

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step-by-step explanation:

it is contrapositive

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