PLZ PLZ HELP I DONT UNDER STAND THIS!! Many games involve chance and they usually involved either dice or cards. For this activity, we will look
at a common game called 7‐11 where two dice are rolled. If the roll adds up to 7 or 11, the player wins.
If the roll adds up to 2, 3, or 12, the player loses. If there is any other sum, it is a draw (no winner or
loser). Use this two‐dice roll scenario to complete the problems below.
. What is the probability for each of the sums below? NOT A MULTIPLE CHOICE.
2=
3=
7=
11=
12=

See below.

Step-by-step explanation:

See the attached chart that shows all outcomes for two dice.

There are 36 possible outcomes, all equally likely (if the dice are fair!).

The probability of getting a sum of 2 is  1/36 (only one way to get 2: both dice show 1).

The probability of getting a sum of 3 is  2/36 = 1/18.

The probability of getting a sum of 7 is 6/36 = 1/6 (the most likely sum!)

(Notice how all the sum = 7 outcomes like on a diagonal in the chart?)

The probability of getting a sum of 11 is  2/36 = 1/18.

The probability of getting a sum of 12 is 1/36.

a = 11 : 4

b = 38

c = 1 for every 6

b

step-by-step explanation: