A ball is launched out of a cannon that is 24 feet off the ground. The height of the ball after "t" seconds is represented by h(t) = -16t² + 20x + 24
How many seconds will it take for the to reach the ground?

Given:

The height of ball is represented by the below function:

To find:

The number of seconds it will take to reach the ground.

Solution:

We have,

At ground level, the height of ball is 0, i.e., .

Taking out greatest common factor.

Splitting the middle term, we get

Using zero product property, we get

and

and

Time cannot be negative, so .

Therefore, the ball will reach the ground after 2 seconds.

step-by-step explanation: