Interpret the results of the chi-square test. A die is rolled 180 times and the following data are obtained. Number Frequency 1 31 2 34 3 26 4 16 5 32 6 41A chi-square test was conducted to determine, at the 5% significance level, whether or not the die is loaded (i. e., that the six numbers are not equally likely).Carry out the hypothesis test.

Step-by-step explanation:

From the given information:

Null and alternative hypothesis is:

Numbers   Observed         Expected            (O - E)    (O-E)^2     (O-E)^2/E

                 Frequency (O)   Frequency (E)  

1                  31                             30                   1             1               0.03

2                 34                            30                   4             16            0.53

3                 26                            30                  -4            16             0.53

4                 16                             30                  -14           196           6.53

5                 32                            30                    2            4               0.13

6                 41                             30                    11            121            4.03

Total          180                                                

degree of freedom = n - 1

= 6 - 1

= 5

Critical value at

Since the calculated , then we reject

Conclusion: Accept the alternative hypothesis.

The information provided gives sufficient evidence for us to conclude that the given die is loaded.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

hello! just here for points! though i wish i knew!