If the results of a survey of senior high school students are normally distributed, and 21,000 students are surveyed, approximately how many students will there be who
have results that produce z-scores between -1 and 2?

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step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

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step-by-step explanation: