The yearbook has 12 pages for ads. Each page measures 6 in. By 12 in. Each ad measures 6 in. By 3 in. If all the ad space sells at ​$10 per​ ad, how much money will this raise for the​ yearbook?

$480

Step-by-step explanation:

Each page measures 6 in. By 12 in. Each ad measures 6 in. By 3 in

based on the dimensions, there would be 4 ads per page

total ads in 12 pages = 4 x 12 = 48

total cost of ads = 48 x 10 = 480

yep

step-by-step explanation:

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".