A hot air balloon is released and it rises at a speed of 15 mph. A weather pattern introduces a wind headed west at 20 mph. The
hot air balloon is now redirected. What was the new speed of the
balloon?

child does not get an education so she can use the molla on junk

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

answer: y=0 if that is what u r looking for