Answer please i need this

Divide. write in simplest form 41/6 divided by 10

Two cars which are 40 miles apart start moving simultaneously in the same direction with constant speeds. if the speed of the car which is behind is 56 mph and the speed of the other car is 48 mph, how many hours will it take for the car which is behind to catch up the car ahead of it?

How can you find the magnitude of a vector, v = < x,y > , where the horizontal change is x and the vertical change is y?