Find the equation of the line that is perpendicular to y = -x - 3
and contains the point (1,2).
y = [? ]x+

Step-by-step explanation:

There is a difference in the two questions, but the result is found the same way

line is in the form y = mx + b

where m is the slope and b is the y intercept.

Perpendicular lines have negative reciprocal slopes

The desired line from the picture has a slope of 5

Now we plug in the included point

2 = 5(1) + b

b = -3

y = 5x - 3

The desired line from the write up has a slope of 1

Now we plug in the included point

2 = (1) + b

b = 1

y = x + 1

ok

step-by-step explanation: