![\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=6^{\frac{1}{4}}2^{-\frac{1}{3}}=\sqrt[12]{(6^{\frac{1}{4}}2^{-\frac{1}{3}})^{12}}=\sqrt[12]{6^32^{-4}}\\\\=\sqrt[12]{6^32^82^{-12}}=\dfrac{\sqrt[12]{6^32^8}}{2}=\boxed{\dfrac{\sqrt[12]{55296}}{2}}](/tpl/images/1356/9023/e757b.png)
Which expression is equivalent to 4 6/3 2
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