Describe the end behavior of the graph of the function. hx()=−3x4+4x3+10x2−8x+7
a. hx()→−∞as x→−∞and hx()→−∞as x→∞
b. hx()→−∞as x→−∞and hx()→∞as x→∞
c. hx()→∞as x→−∞and hx()→−∞as x→∞
d. hx()→∞as x→−∞and hx()→∞as x→∞

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  a.hx()→−∞as x→−∞and hx()→−∞as x→∞

Step-by-step explanation:

The negative leading coefficient tells you the function tends toward -∞ as x gets large. The even degree tells you it goes the same direction as x tends toward -∞.

  h(x) → -∞  for x large or small . . . . matches A

2

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length