A ball is thrown into the air with an upward velocity of 40 ft/s. Its height h in feet after t seconds is given by the function \large h=-16t^2+40t. What is the ball's maximum height?

Step-by-step explanation:

From the question we are told that:

Velocity

The height h function

Generally time t is mathematically given by

Therefore  the ball's maximum height is given as

y=mx+

is there any photos or whatever?