in the bag, there are certain number of toy- blocks with alphabets A, B,C and D written on them. The ratio of blocks A:B:C:D is 4:7:3:1. if the number of A blocks is 50 more than the number of C blocks, what is the number of B blocks?​

Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1

Let us consider the common ratio to be ‘x’.

So, toy blocks with alphabet A is 4x and

toy blocks with alphabet B is 7x and

toy blocks with alphabet C is 3x and

toy blocks with alphabet D is x

Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.

As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.

So,

4x=50 + 3x

x=50

Thus, the number of ‘B’ blocks is 7x = 7(50) = 350

350 is the required number.