Resuelve los siguientes triángulos rectángulos encontrando todos los datos faltantes ​

Respuesta:

A = 51,167

b = 28,5 pies

c = 45,4 pies

Explicación paso a paso:

C = 90 °

B = 38 ° 50 '

Convertir B a grado

1 ° = 60 '

x ° = 50 '

Multiplicar en cruz:

60x = 50

x = 50/60

x = 0,83333 °

Por lo tanto, 38 ° 50 '= 38 ° + 0.833 ° = 38.833 °

Recordar :

A + B + C = 180 ° (Suma de ángulos en un triángulo)

A + 38.833 + 90 = 180

A + 128.833 = 180

A = 180 - 128,833

A = 51,167 °

Usando identidades trigonométricas, podríamos encontrar byc

Para obtener b:

Tan B = opuesto / adyacente = b / 35.4

Tan 38,833 = b / 35,4

b = Tan 38,833 * 35,4

b = 28,5 pies

Para obtener c:

Podríamos usar:

Sin A = opuesto / hipoteno = 35,4 / c

Sin 51,167 = 35,4 / c

c * sin 51,167 = 35,4

c = 35,4 / sen 51,167

c = 45,4 pies

answer: idk

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.