A rectangular-shaped school courtyardhas a length of 280 feet and a width of150 feet wide. What is the approximatelength of a diagonal of the courtyard tothe nearest tenth?

317.6 feet

Step-by-step explanation:

the length of the diagonal can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

280²  + 150²

= 78,400 + 22,500

= 100,900

take the square root of  100,900

= 317.648 feet

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

317.6 to the nearest tenth

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

do your own work and don"t cheat.

step-by-step explanation: