a ladder 10 m long leans against the wall of a building. if the foot of the ladder makes an angle of 65 degree with the ground, how far is the ladder based from the whole?​

Step-by-step explanation:

cos theta=b/h

cos65°=b/10

b=0.522×10

b=5.22m

so,the base of ladder is 5.22m far from the whole.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this