Write the equation of a line perpendicular to the line: y=43x−1 that goes through the point (-6, -6).
Write your answer in slope- intercept form, using reduced fractions for the slope and intercept.
y-__=__(x-__)
y=__x+__

Given:

The equation of perpendicular line is:

The required line passes through the point is (-6,-6).

To find:

The equation of the line.

Solution:

The slope intercept form of a line is:

              ...(i)

Where, m is the slope and b is the y-intercept.

We have,

          ...(ii)

On comparing (i) and (ii), we get

Slope of given line is .

The product of slopes of two perpendicular line is -1.

So, the slope of the required line is . It passes through the point is (-6,-6). So, the equation of the line is:

On further simplification, we get

Therefore, equations of the required line are and .

answer: 45

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.