If 1-log (x+1) = log(x-8) find the possible values of X

9

Step-by-step explanation:

1-log (x+1) = log(x-8)

<=> log 10 -log (x+1) = log(x-8)

10/(x+1)=(x-8)

=> (x+1) (x-8)= 10

x²-7x-8=10

x²-7x-18=0

(x-9) (x+2)=0

x=9 or x=-2

so, x=9 is the possible value

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

false

ajkdfbwladnfwisafrw