The only solution to x² + bx + c = 0
is x = 5

work out the values of b and c​

Answers:

b = -10

c = 25

Explanation:

If x = 5 is the only solution then (x-5) is the only factor. Turns out we have repeated solutions and repeated factors. Meaning (x-5)(x-5) = (x-5)^2 is what we're after.

Expand that out to get

(x-5)^2

x^2 - 5x - 5x + 25

x^2 - 10x + 25

Then compare this to x^2 + bx + c to find

b = -10

c = 25

If you were to solve x^2-10x+25 = 0, you'll find that x = 5 is the only root.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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