How do you find the radius of a Tetrahedron? My own question no answer choices.
No bit links plz. 15 points and plz describe well.

The center of the tetrahedron divides each of the four heights (or medians) in the ratio 1:3 (in an equilateral triangle the corresponding ratio is 1:2). The smaller part is also the radius of the inscribed sphere. Therefore the radius of this sphere is one quarter of the height or 9 in your case.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it