In a 3-digit number, the hundreds is one more than the ones digit and tens digit is twice the hundred digit. If the the sum of the digits is 11, find the number.

362

Step-by-step explanation:

Let u = the units digit

2(u + 1) = the tens digit

u + 1 = the hundreds digit

u + 2(u + 1) + u + 1 = 11

u + 2u + 2 + u + 1 = 11

4u + 3 = 11

4u = 8

u = 2 = ones digit

u + 1 = 3 = hundreds digit

2(u + 1) = 2(3) = 6

The number is 362

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°