Write the standard equation for the circle whose center is at ​(6​,2​) and whose radius is 2.

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Step-by-step explanation:

In general, let denote the center of a given circle. Let denote the radius of that circle. The standard equation for that circle would be:

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The circle in this question is centered at .  

The radius of this circle is . Therefore, .

Hence, the standard equation for this circle would be:

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step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

care to share were the trapezoid shown is ?