Casey boards a Ferris wheel at the 3-o'clock position and rides the Ferris wheel for multiple revolutions. The Ferris wheel rotates at a constant angular speed of 5.6 radians per minute and has a radius of 50 feet. The center of the Ferris wheel is 55 feet above the ground. Let t represent the number of minutes since the Ferris wheel started rotating. a. Write an expression (in terms of t) to represent the varying number of radians θ Ryan has swept out since the ride started.
b. Write an expression (in terms of t) to represent Ryan's height (in feet) above the ground.

Solution :

It is given that :

Casey boarded a Ferry wheel at position of 3 'o' clock.

The angular speed of the Ferry wheel = 5.6 radians per minute

The radius of the Ferry wheel = 50 feet

The height of the center wheel of the Ferry from the ground = 55 feet

Let the number of minutes be = t

a). The expression of the varying number of radians θ is given by :

After t minutes,  θ = angle swept

                           θ = 5.6 t radians

b). Finding the height from the center of the wheel.

We know that : y = r sin θ

Given r = 50 feet

So, y = 50 sin (5.6 t) feet

Therefore, the height above the ground can be found by :

h = y + 55 (from ground)

h = 50 sin (5.6 t) + 55   feet

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°