A right cylindrical vase holds 2.50 L of water. If the radius of the vase is 9.00 cm, what is the height of the vase, rounded to the nearest hundredth of a centimeter? (Note: 1 cm3 = 0.001L)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

c. (3,2,6) is the answer.

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step-by-step explanation: vsfdvsfvd