Let 0 be an angle such that sec0= -13/12 and cot0<0. Find the exact values of tan0 and sin0.

Solution given;

Sec θ=-

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

cosθ=

=

b=12

h=13

By using Pythagoras law

p=

Now

exact values of tan θ==

since it lies in II quadrant

tan θ=-

and

sinθ==

since it lies in II quadrant

sin θ=

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole

cbnygjdyj

step-by-step explanation: