You are wrapping a birthday gift that is packaged in a specially made pyramid-shaped box. The base of the box measures 10 inches by 9 inches and the slant height is 6 inches. How much paper do you need to wrap the box

2826  inches^2

Step-by-step explanation:

The general formula for the total surface area of a regular pyramid is

T.S.A.=12pl+B

Where p represents the perimeter of the base, l the slant height and B the area of the base.

The perimeter of the base is.  

p=2L+2W

P=2*10+2*9

P=20+18

P= 38  inches

The area of the base is.

B=10*9

B=90in^2

T.S.A.=12(38)(6)+90              

T.S.A=2736+90

T.S.A=2826  inches^2

Hence the paper needed is 2826  inches^2

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

answer: i don't understand it

step-by-step explanation: sorry