Suppose you save $1 the first day of a month, $4 the second day, $16 the third day, and so on. That is, each day you save four times as much as you did the day before. What will you put aside for savings on the seventh day of the month?

$ 4096 on the 7th day

Step-by-step explanation:

From the amount earned for the first 3 days it's 1 , 4 , 16 , We realize it increases exponentially.

So therefore:

Day 1 =4⁰

Day 2=4¹

Day 3=4²

Day 4=4³

Day 5=4⁴

Day 6=4⁵

Day 7=4⁶

Therefore on day 7 he saves 4⁶ which is $4096

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

idk

step-by-step explanation:

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