(20 points) Of all the TVs of a certain model that are sold, 10% require repair to be done under the warranty during the first year service. A particular dealership sells 18 such TV per week. a) What is the probability that exactly two of them require warranty repairs

0.2835 = 28.35% probability that exactly two of them require warranty repairs.

Step-by-step explanation:

For each TV, there are only two possible outcomes. Either they require warranty repairs, or they do not. The probability of a TV requiring warranty repairs is independent of any other TV, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

10% require repair to be done under the warranty during the first year service.

This means that

A particular dealership sells 18 such TV per week.

This means that

a) What is the probability that exactly two of them require warranty repairs?

This is . So

0.2835 = 28.35% probability that exactly two of them require warranty repairs.

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5