A ball is thrown from a height of 45 meters with an initial downward velocity of 12 meters per second. the ball's height h (in meters) after t seconds is given by the following: h=45-12t-5t^2 . How long after the ball is thrown does it hit the ground. Round the answer(s) to the nearest hundredth.

y=mx+b

step-by-step explanation:

m slope, b y-intercept

7/2

(decimal: 3.5)

welcome ; )

step-by-step explanation:

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

answer: idk wbu

step-by-step explanation: umm..