A number has the same digit in its hundreds place and its hundredths place. How many times greater is the value of the digit in the hundredths place than the value of the digit in the hundredths place?​

A number has the same digit in its hundreds place and its hundredths place. Let the digit be '1'. Hence, the the value of the digit in the hundreds place is 10,000 times greater than the value of the digit in the hundredths place

Step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7