Can somebody please help me

Step-by-step explanation:

For y = 2^x:

f(-3) = 2^-3. f(-2) = 2^-2. f(-1) = 2^-1

= 1/8 = 1/4. =1/2

f(0) = 2^0 f(1) = 2^1. f(2) = 2^2

= 1 = 2. =4

f(3) = 2^3

=8

For 3y = 7x + 3, y= (7x+3)/3

f(-3) = [7(-3)+3] / 3. f(-2) = [7(-2)+3] / 3

= -6. = -11/3

f(-1) = [7(-1)+3] / 3. f(0) = [7(0)+3] / 3

= -4/3 = 1

f(1) = [7(1)+3] / 3. f(2) = [7(2)+3] / 3

= 10/3 = 17/3

f(3) = [7(3)+3] / 3.

= 8

point of intersection, where y=2^x and 3y = 7x + 3 has the same x and y coordinate

(0,1) and (3,8)

c.35

step-by-step explanation:

8+13=21

21+8=29

29+6=35

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: