![subject](/tpl/images/cats/mat.png)
Module 6
Students will identify angles of rotation, reference angles, and the trig ratios for a terminal ray through a
given point. Students will evaluate the 6 trig ratios at angles of rotation given in degrees and radians.
1. Draw a terminal ray through the point (-3,- 313) making an angle of rotation "o" in standard position.
Then give the following ratios: (for graphing use 313 25.2)
y-axis
4
I
sin -
COS =
tan =
2
X-axis
CSC =
sec =
cot =
6 -5 4 ) -2
-1
1
2
4 5 6
-2
Reference Angle =
![ansver](/tpl/images/cats/User.png)
![ansver](/tpl/images/cats/User.png)
answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.
step-by-step explanation:
radius is diameter/2 = 4.
area of circle is π r^2.
volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.
not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).
volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.
r(y) = r - r/h y
area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)
antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))
integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h
volume of this cone is π/3(4^2)18 cubic inches.
= 6 16 π = 96π cubic inches.
cone has twice the volume, 96/48.
cone height is 6 times the cylinder.
ratio of volume formula: π r^2 cancels.
cone over cylinder ratio is 6h/3 to h, 2 to 1.
![ansver](/tpl/images/cats/User.png)
mr. india
![ansver](/tpl/images/cats/User.png)
idk
step-by-step explanation:
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