Fill in the blanks. Suppose the probability at a light bulb factory of a bulb being defective is 0.11. If a shipment of 133 bulbs is sent out, the number of defective bulbs in the shipment should be around , give or take . Assume each bulb is independent.

The number of defective bulbs in the shipment should be around 15, give or take 4.

Step-by-step explanation:

For each bulb, there are only two possible outcomes. Either it is defective, or it is not. The probability of a bulb being defective is independent of any other bulb. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

The standard deviation of the binomial distribution is:

Suppose the probability at a light bulb factory of a bulb being defective is 0.11

This means that

Shipment of 133 bulbs:

This means that

Mean and standard deviation:

Rounding to the nearest integers:

The number of defective bulbs in the shipment should be around 15, give or take 4.

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