Given k > 3 and ( +
2x+2) dx = 10k
show that k3 – 10k2 + ak + b = 0
where a and bare constants to be found.

See Below.

Step-by-step explanation:

We are given that:

And we want to show that:

Integrate the definite integral:

Evaluate:

Simplify:

Multiply both sides by k:

Rewrite:

Hence, a = -7 and b = -6.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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