jabu left town A to travel to town B at 6:00 a. m. he drove at an average speed of 80km/h. At 8.30a. m. Sipho left town A to travel to town B. He drove at an average speed of 100 km/h. At what time will Sipho catch up jabu?​

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

At what time will Sipho catch up jabu?​

He will catch up in t hours, and t is found when:

So

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5