If the area of a square is 9, then the perimeter of the
square is

Hi there!  

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I believe your answer is:  

12 units.  

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Here’s why:  

The formula for area of a square is:

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Recall that the area of a square is the square of it's side length. ⸻⸻⸻⸻

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The side length of the square is 3 units.

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The formula for perimeter of a square is:

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Recall that the perimeter of a square is 4 times the side length. .

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The perimeter of the square is 12 units.

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Hope this helps you. I apologize if it’s incorrect.  

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.