Students at Elon University were surveyed and the average commute distance to campus is 0.5 mile. Assume the population standard deviation is 0.1 mile. Please construct a 90% confidence interval for the population mean. a. [0.472, 0.528]
b. [0.479, 0.521)
c. [0.463, 0.534]
d. [0.476, 0.524]

The 90% confidence interval for the population mean is , in which n is the number of students surveyed.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

That is z with a pvalue of , so Z = 1.645.

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M, while the upper end is M added to the sample mean of 0.5. Thus, the confidence interval is of:

The 90% confidence interval for the population mean is , in which n is the number of students surveyed.

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .